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Mathematics I - Introduction

21/22

(2)

Why study Math?

http://www.karlin.mff.cuni.cz/∼pick/2018-10-02-prvni-prednaska-z-analyzy.pdf

https://www.youtube.com/watch?v=6eC3ndnR86s https://fanmovie.cz/dvd/alenka-v-risi-divu-na-dvd-a-blu-ray/ http://ceskapozice.lidovky.cz/nove-relikvie-z-mendelovy-pozustalosti-otec-genetiky-laka-vedce-do-ceska-1q6- /tema.aspx?c=A121220 120247 pozice 88014

https://g.cz/pred-77-lety-byl-cepinem-zavrazden-bolsevik-trockij-po-propusteni-z-vezeni-zil-jeho-vrah-kousek-za-prahou/

Mathematics I - Introduction 2 / 48

(3)

Why study Math?

http://www.karlin.mff.cuni.cz/∼pick/2018-10-02-prvni-prednaska-z-analyzy.pdf

https://www.youtube.com/watch?v=6eC3ndnR86s https://fanmovie.cz/dvd/alenka-v-risi-divu-na-dvd-a-blu-ray/ http://ceskapozice.lidovky.cz/nove-relikvie-z-mendelovy-pozustalosti-otec-genetiky-laka-vedce-do-ceska-1q6- /tema.aspx?c=A121220 120247 pozice 88014

https://g.cz/pred-77-lety-byl-cepinem-zavrazden-bolsevik-trockij-po-propusteni-z-vezeni-zil-jeho-vrah-kousek-za-prahou/

(4)

Why study Math?

http://www.karlin.mff.cuni.cz/∼pick/2018-10-02-prvni-prednaska-z-analyzy.pdf

https://www.youtube.com/watch?v=6eC3ndnR86s https://fanmovie.cz/dvd/alenka-v-risi-divu-na-dvd-a-blu-ray/ http://ceskapozice.lidovky.cz/nove-relikvie-z-mendelovy-pozustalosti-otec-genetiky-laka-vedce-do-ceska-1q6- /tema.aspx?c=A121220 120247 pozice 88014

https://g.cz/pred-77-lety-byl-cepinem-zavrazden-bolsevik-trockij-po-propusteni-z-vezeni-zil-jeho-vrah-kousek-za-prahou/

Mathematics I - Introduction 2 / 48

(5)

Why study Math?

http://www.karlin.mff.cuni.cz/∼pick/2018-10-02-prvni-prednaska-z-analyzy.pdf

https://www.youtube.com/watch?v=6eC3ndnR86s https://fanmovie.cz/dvd/alenka-v-risi-divu-na-dvd-a-blu-ray/ http://ceskapozice.lidovky.cz/nove-relikvie-z-mendelovy-pozustalosti-otec-genetiky-laka-vedce-do-ceska-1q6- /tema.aspx?c=A121220 120247 pozice 88014

https://g.cz/pred-77-lety-byl-cepinem-zavrazden-bolsevik-trockij-po-propusteni-z-vezeni-zil-jeho-vrah-kousek-za-prahou/

(6)

Why study Math?

http://www.karlin.mff.cuni.cz/∼pick/2018-10-02-prvni-prednaska-z-analyzy.pdf

https://www.youtube.com/watch?v=6eC3ndnR86s https://fanmovie.cz/dvd/alenka-v-risi-divu-na-dvd-a-blu-ray/

http://ceskapozice.lidovky.cz/nove-relikvie-z-mendelovy-pozustalosti-otec-genetiky-laka-vedce-do-ceska-1q6- /tema.aspx?c=A121220 120247 pozice 88014

https://g.cz/pred-77-lety-byl-cepinem-zavrazden-bolsevik-trockij-po-propusteni-z-vezeni-zil-jeho-vrah-kousek-za-prahou/

Mathematics I - Introduction 2 / 48

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Goal of the course

Preparation for other courses — Statistics, Microeconomics, . . .

Training of logical thinking and mathematical exactness

At the end of the course students should be able to

compute limits and derivatives and investigate functions understand definitions (give positive and negative

examples) and theorems (explain their meaning, neccessity of the assumptions, apply them in particular situations) perform mathematical proofs, give mathematically exact arguments, write mathematical formulae, use quantifiers

(8)

Goal of the course

Preparation for other courses — Statistics, Microeconomics, . . .

Training of logical thinking and mathematical exactness At the end of the course students should be able to

compute limits and derivatives and investigate functions understand definitions (give positive and negative

examples) and theorems (explain their meaning, neccessity of the assumptions, apply them in particular situations) perform mathematical proofs, give mathematically exact arguments, write mathematical formulae, use quantifiers

Mathematics I - Introduction 3 / 48

(9)

Goal of the course

Preparation for other courses — Statistics, Microeconomics, . . .

Training of logical thinking and mathematical exactness At the end of the course students should be able to

compute limits and derivatives and investigate functions

understand definitions (give positive and negative

examples) and theorems (explain their meaning, neccessity of the assumptions, apply them in particular situations) perform mathematical proofs, give mathematically exact arguments, write mathematical formulae, use quantifiers

(10)

Goal of the course

Preparation for other courses — Statistics, Microeconomics, . . .

Training of logical thinking and mathematical exactness At the end of the course students should be able to

compute limits and derivatives and investigate functions understand definitions (give positive and negative

examples) and theorems (explain their meaning, neccessity of the assumptions, apply them in particular situations)

perform mathematical proofs, give mathematically exact arguments, write mathematical formulae, use quantifiers

Mathematics I - Introduction 3 / 48

(11)

Goal of the course

Preparation for other courses — Statistics, Microeconomics, . . .

Training of logical thinking and mathematical exactness At the end of the course students should be able to

compute limits and derivatives and investigate functions understand definitions (give positive and negative

examples) and theorems (explain their meaning, neccessity of the assumptions, apply them in particular situations) perform mathematical proofs, give mathematically exact arguments, write mathematical formulae, use quantifiers

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Mathematics I

Introduction

Limit of a sequence Mappings

Functions of one real variable

Mathematics I - Introduction 4 / 48

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Textbooks

H´ajkov´a et al: Mathematics 1 Trench: Introduction to real analysis

Ghorpade, Limaye: A course in calculus and real analysis Zorich: Mathematical analysis I

Rudin: Principles of mathematical analysis

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Sets

We take a set to be a collection of definite and distinguishable objects into a coherent whole.

x∈A. . .xis an element (or member) of the setA

Exercise (True or false)

A- set of all animals living in Australia.

A a∈A B b∈A C c∈A D d ∈A E e∈A

Mathematics I - Introduction 6 / 48

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Sets

We take a set to be a collection of definite and distinguishable objects into a coherent whole.

x∈A. . .xis an element (or member) of the setA

Exercise (True or false)

A- set of all animals living in Australia.

A a∈A B b∈A C c∈A D d ∈A E e∈A

(16)

Sets

We take a set to be a collection of definite and distinguishable objects into a coherent whole.

x∈A. . .xis an element (or member) of the setA

Exercise (True or false)

A- set of all animals living in Australia.

A a∈A B b∈A C c∈A D d ∈A E e∈A

Mathematics I - Introduction 6 / 48

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Sets

We take a set to be a collection of definite and distinguishable objects into a coherent whole.

x∈A. . .xis an element (or member) of the setA

Exercise (True or false)

A- set of all animals living in Australia.

A a∈A B b∈A C c∈A D d ∈A E e∈A

(18)

Sets

We take a set to be a collection of definite and distinguishable objects into a coherent whole.

x∈A. . .xis an element (or member) of the setA Exercise (True or false)

A- set of all animals living in Australia.

A a∈A B b∈A C c∈A D d ∈A E e∈A

Mathematics I - Introduction 6 / 48

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Sets

x∈/ A. . .xis not a member of the setA

Exercise (True or false)

A- set of all animals living in Australia.

A a̸∈A B b̸∈A C c̸∈A D d ̸∈A E e̸∈A

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Sets

x∈/ A. . .xis not a member of the setA Exercise (True or false)

A- set of all animals living in Australia.

A a̸∈A B b̸∈A C c̸∈A D d ̸∈A E e̸∈A

Mathematics I - Introduction 7 / 48

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Sets

Ac. . . the complement of the setA

B⊂A. . . the setBis a subset of the setA(inclusion) Example:Bis the set of all birds living in Australia:B⊂A. A=B. . . the setsAandBhave the same elements; the following holds:A⊂BandB⊂A

∅. . . an empty set

A∪B. . . the union of the setsAandB A∩B. . . the intersection of the setsAandB disjoint sets . . .AandBare disjoint ifA∩B=∅

A\B={x∈A; x∈/ B}. . . a difference of the setsAandB A1× · · · ×Am={[a1, . . . ,am]; a1 ∈A1, . . . ,am∈Am} . . . the Cartesian product

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Sets

Ac. . . the complement of the setA

B⊂A. . . the setBis a subset of the setA(inclusion) Example:Bis the set of all birds living in Australia:B⊂A.

A=B. . . the setsAandBhave the same elements; the following holds:A⊂BandB⊂A

∅. . . an empty set

A∪B. . . the union of the setsAandB A∩B. . . the intersection of the setsAandB disjoint sets . . .AandBare disjoint ifA∩B=∅

A\B={x∈A; x∈/ B}. . . a difference of the setsAandB A1× · · · ×Am={[a1, . . . ,am]; a1 ∈A1, . . . ,am∈Am} . . . the Cartesian product

Mathematics I - Introduction 8 / 48

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Sets

Ac. . . the complement of the setA

B⊂A. . . the setBis a subset of the setA(inclusion) Example:Bis the set of all birds living in Australia:B⊂A.

A=B. . . the setsAandBhave the same elements; the following holds:A⊂BandB⊂A

∅. . . an empty set

A∪B. . . the union of the setsAandB A∩B. . . the intersection of the setsAandB disjoint sets . . .AandBare disjoint ifA∩B=∅

A\B={x∈A; x∈/ B}. . . a difference of the setsAandB A1× · · · ×Am={[a1, . . . ,am]; a1 ∈A1, . . . ,am∈Am} . . . the Cartesian product

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Sets

Ac. . . the complement of the setA

B⊂A. . . the setBis a subset of the setA(inclusion) Example:Bis the set of all birds living in Australia:B⊂A.

A=B. . . the setsAandBhave the same elements; the following holds:A⊂BandB⊂A

∅. . . an empty set

A∪B. . . the union of the setsAandB A∩B. . . the intersection of the setsAandB disjoint sets . . .AandBare disjoint ifA∩B=∅

A\B={x∈A; x∈/ B}. . . a difference of the setsAandB A1× · · · ×Am={[a1, . . . ,am]; a1 ∈A1, . . . ,am∈Am} . . . the Cartesian product

Mathematics I - Introduction 8 / 48

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Sets

Ac. . . the complement of the setA

B⊂A. . . the setBis a subset of the setA(inclusion) Example:Bis the set of all birds living in Australia:B⊂A.

A=B. . . the setsAandBhave the same elements; the following holds:A⊂BandB⊂A

∅. . . an empty set

A∪B. . . the union of the setsAandB

A∩B. . . the intersection of the setsAandB disjoint sets . . .AandBare disjoint ifA∩B=∅

A\B={x∈A; x∈/ B}. . . a difference of the setsAandB A1× · · · ×Am={[a1, . . . ,am]; a1 ∈A1, . . . ,am∈Am} . . . the Cartesian product

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Sets

Ac. . . the complement of the setA

B⊂A. . . the setBis a subset of the setA(inclusion) Example:Bis the set of all birds living in Australia:B⊂A.

A=B. . . the setsAandBhave the same elements; the following holds:A⊂BandB⊂A

∅. . . an empty set

A∪B. . . the union of the setsAandB A∩B. . . the intersection of the setsAandB

disjoint sets . . .AandBare disjoint ifA∩B=∅

A\B={x∈A; x∈/ B}. . . a difference of the setsAandB A1× · · · ×Am={[a1, . . . ,am]; a1 ∈A1, . . . ,am∈Am} . . . the Cartesian product

Mathematics I - Introduction 8 / 48

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Sets

Ac. . . the complement of the setA

B⊂A. . . the setBis a subset of the setA(inclusion) Example:Bis the set of all birds living in Australia:B⊂A.

A=B. . . the setsAandBhave the same elements; the following holds:A⊂BandB⊂A

∅. . . an empty set

A∪B. . . the union of the setsAandB A∩B. . . the intersection of the setsAandB disjoint sets . . .AandBare disjoint ifA∩B=∅

A\B={x∈A; x∈/ B}. . . a difference of the setsAandB A1× · · · ×Am={[a1, . . . ,am]; a1 ∈A1, . . . ,am∈Am} . . . the Cartesian product

(28)

Sets

Ac. . . the complement of the setA

B⊂A. . . the setBis a subset of the setA(inclusion) Example:Bis the set of all birds living in Australia:B⊂A.

A=B. . . the setsAandBhave the same elements; the following holds:A⊂BandB⊂A

∅. . . an empty set

A∪B. . . the union of the setsAandB A∩B. . . the intersection of the setsAandB disjoint sets . . .AandBare disjoint ifA∩B=∅

A\B={x∈A; x∈/ B}. . . a difference of the setsAandB

A1× · · · ×Am={[a1, . . . ,am]; a1 ∈A1, . . . ,am∈Am} . . . the Cartesian product

Mathematics I - Introduction 8 / 48

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Sets

Ac. . . the complement of the setA

B⊂A. . . the setBis a subset of the setA(inclusion) Example:Bis the set of all birds living in Australia:B⊂A.

A=B. . . the setsAandBhave the same elements; the following holds:A⊂BandB⊂A

∅. . . an empty set

A∪B. . . the union of the setsAandB A∩B. . . the intersection of the setsAandB disjoint sets . . .AandBare disjoint ifA∩B=∅

A\B={x∈A; x∈/ B}. . . a difference of the setsAandB A1× · · · ×Am={[a1, . . . ,am]; a1 ∈A1, . . . ,am∈Am} . . . the Cartesian product

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Sets - questions

Exercise

LetU ={1,2,3,4,5,6,7,8,9},A={1,3,5,7,9}and B={1,2,3,4,5}. Find

1. A∪B 2. A∩B

3. Ac 4. (Bc)c

5. A\B 6. B\A

Exercise (True or false) LetAbe a set.

A ∅ ∈A B ∅ ⊂A C 0=∅

D {x} ∈ {x,y,z} E x∈ {x,y,z}

Mathematics I - Introduction 9 / 48

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Sets - questions

Exercise

LetU ={1,2,3,4,5,6,7,8,9},A={1,3,5,7,9}and B={1,2,3,4,5}. Find

1. A∪B 2. A∩B

3. Ac 4. (Bc)c

5. A\B 6. B\A

Exercise (True or false) LetAbe a set.

A ∅ ∈A B ∅ ⊂A C 0=∅

D {x} ∈ {x,y,z}

E x∈ {x,y,z}

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Sets

A1× · · · ×Am={[a1, . . . ,am]; a1 ∈A1, . . . ,am∈Am}. . . the Cartesian product

Exercise

LetA={1,2,3},B={2,4}. FindA×B,B×Band sketch them.

Mathematics I - Introduction 10 / 48

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Sets

A1× · · · ×Am={[a1, . . . ,am]; a1 ∈A1, . . . ,am∈Am}. . . the Cartesian product

Exercise

LetA={1,2,3},B={2,4}. FindA×B,B×Band sketch them.

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Sets

LetIbe a non-empty set of indices and suppose we have a system of setsAα, where the indicesαrun overI.

S

α∈I

Aα. . . the set of all elements belonging to at least one of the setsAα

T

α∈I

Aα. . . the set of all elements belonging to everyAα Example.

A1∪A2∪A3is equivalent to

3

S

i=1

Ai, and also to S

i∈{1,2,3}

Ai. Infinitely many sets:A1∪A2∪A3∪. . . is equivalent to

S

i=1

Ai, and also to S

i∈N

Ai.

Mathematics I - Introduction 11 / 48

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Sets

LetIbe a non-empty set of indices and suppose we have a system of setsAα, where the indicesαrun overI.

S

α∈I

Aα. . . the set of all elements belonging to at least one of the setsAα

T

α∈I

Aα. . . the set of all elements belonging to everyAα

Example.

A1∪A2∪A3is equivalent to

3

S

i=1

Ai, and also to S

i∈{1,2,3}

Ai. Infinitely many sets:A1∪A2∪A3∪. . . is equivalent to

S

i=1

Ai, and also to S

i∈N

Ai.

(36)

Sets

LetIbe a non-empty set of indices and suppose we have a system of setsAα, where the indicesαrun overI.

S

α∈I

Aα. . . the set of all elements belonging to at least one of the setsAα

T

α∈I

Aα. . . the set of all elements belonging to everyAα

Example.

A1∪A2∪A3is equivalent to

3

S

i=1

Ai, and also to S

i∈{1,2,3}

Ai. Infinitely many sets:A1∪A2∪A3∪. . . is equivalent to

S

i=1

Ai, and also to S

i∈N

Ai.

Mathematics I - Introduction 11 / 48

(37)

Sets

LetIbe a non-empty set of indices and suppose we have a system of setsAα, where the indicesαrun overI.

S

α∈I

Aα. . . the set of all elements belonging to at least one of the setsAα

T

α∈I

Aα. . . the set of all elements belonging to everyAα Example.

A1∪A2∪A3is equivalent to

3

S

i=1

Ai, and also to S

i∈{1,2,3}

Ai. Infinitely many sets:A1∪A2∪A3∪. . . is equivalent to

S

i=1

Ai, and also to S

i∈N

Ai.

(38)

Sets

LetIbe a non-empty set of indices and suppose we have a system of setsAα, where the indicesαrun overI.

S

α∈I

Aα. . . the set of all elements belonging to at least one of the setsAα

T

α∈I

Aα. . . the set of all elements belonging to everyAα Example.

A1∪A2∪A3is equivalent to

3

S

i=1

Ai, and also to S

i∈{1,2,3}

Ai.

Infinitely many sets:A1∪A2∪A3∪. . . is equivalent to

S

i=1

Ai, and also to S

i∈N

Ai.

Mathematics I - Introduction 11 / 48

(39)

Sets

LetIbe a non-empty set of indices and suppose we have a system of setsAα, where the indicesαrun overI.

S

α∈I

Aα. . . the set of all elements belonging to at least one of the setsAα

T

α∈I

Aα. . . the set of all elements belonging to everyAα Example.

A1∪A2∪A3is equivalent to

3

S

i=1

Ai, and also to S

i∈{1,2,3}

Ai. Infinitely many sets:A1∪A2∪A3∪. . . is equivalent to

S

i=1

Ai, and also to S

i∈N

Ai.

(40)

Sets

Exercise

LetA1 ={0,1},A2 ={0,2},A3 ={0,3}. Find 1.

3

[

i=1

Ai 2. \

i∈{1,2,3}

Ai

Mathematics I - Introduction 12 / 48

(41)

Logic

Astatement(or proposition) is a sentence which can be declared to be either true or false.

Exercise

Find statements. A Let it be!

B We all live in a yellow submarine. C Is there anybody out there? D We don’t need no education.

(42)

Logic

Astatement(or proposition) is a sentence which can be declared to be either true or false.

Exercise

Find statements. A Let it be!

B We all live in a yellow submarine. C Is there anybody out there? D We don’t need no education.

Mathematics I - Introduction 13 / 48

(43)

Logic

Astatement(or proposition) is a sentence which can be declared to be either true or false.

Exercise

Find statements.

A Let it be!

B We all live in a yellow submarine.

C Is there anybody out there?

D We don’t need no education.

(44)

Statements

¬, alsonon. . .negation

& (also∧) . . .conjunction, logical “and”

∨. . .disjuction(alternative), logical “or”

⇒. . .implication

⇔. . .equivalence; “if and only if”

Exercise

1. Alice does not like chocolate icecream.

2. Alice likes chocolate and lemon icecream.

3. Alice likes chocolate or lemon icecream.

4. If it will be raining tomorrow, we will play board games.

5. We will play board games tomorrow if and only if it will be raining.

Mathematics I - Introduction 14 / 48

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Apredicate(or propositional function) is an expression or sentence involving variables which becomes a statement once we substitute certain elements of a given set for the variables.

General form:

V(x),x∈M

V(x1, . . . ,xn),x1 ∈M1, . . . ,xn ∈Mn

Example V(x):xis even M={1,2,3,4,5} V(3)false,V(4)true. V(x1,x2):x1·x2 =1 M={2,12,3,4}

V(2,12)true,V(2,3)false.

(46)

Apredicate(or propositional function) is an expression or sentence involving variables which becomes a statement once we substitute certain elements of a given set for the variables.

General form:

V(x),x∈M

V(x1, . . . ,xn),x1 ∈M1, . . . ,xn ∈Mn

Example V(x):xis even M={1,2,3,4,5} V(3)false,V(4)true. V(x1,x2):x1·x2 =1 M={2,12,3,4}

V(2,12)true,V(2,3)false.

Mathematics I - Introduction 15 / 48

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Apredicate(or propositional function) is an expression or sentence involving variables which becomes a statement once we substitute certain elements of a given set for the variables.

General form:

V(x),x∈M

V(x1, . . . ,xn),x1 ∈M1, . . . ,xn ∈Mn

Example V(x):xis even M={1,2,3,4,5}

V(3)false,V(4)true.

V(x1,x2):x1·x2 =1 M={2,12,3,4}

V(2,12)true,V(2,3)false.

(48)

IfA(x),x∈M is a predicate, then the statement “A(x)holds for everyxfromM.” is shortened to

∀x∈M: A(x).

The statement “There existsxinM such thatA(x)holds.” is shortened to

∃x∈M: A(x).

The statement “There is only onexinMsuch thatA(x)holds.” is shortened to

∃!x∈M: A(x).

Example

∀x∈R:|x| ≥0

∃x∈Q:x+3≤12

∃!x∈R+ :x2=42

Mathematics I - Introduction 16 / 48

(49)

IfA(x),x∈M is a predicate, then the statement “A(x)holds for everyxfromM.” is shortened to

∀x∈M: A(x).

The statement “There existsxinM such thatA(x)holds.” is shortened to

∃x∈M: A(x).

The statement “There is only onexinMsuch thatA(x)holds.” is shortened to

∃!x∈M: A(x).

Example

∀x∈R:|x| ≥0

∃x∈Q:x+3≤12

∃!x∈R+ :x2=42

(50)

IfA(x),x∈M is a predicate, then the statement “A(x)holds for everyxfromM.” is shortened to

∀x∈M: A(x).

The statement “There existsxinM such thatA(x)holds.” is shortened to

∃x∈M: A(x).

The statement “There is only onexinM such thatA(x)holds.”

is shortened to

∃!x∈M: A(x).

Example

∀x∈R:|x| ≥0

∃x∈Q:x+3≤12

∃!x∈R+ :x2=42

Mathematics I - Introduction 16 / 48

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IfA(x),x∈M is a predicate, then the statement “A(x)holds for everyxfromM.” is shortened to

∀x∈M: A(x).

The statement “There existsxinM such thatA(x)holds.” is shortened to

∃x∈M: A(x).

The statement “There is only onexinM such thatA(x)holds.”

is shortened to

∃!x∈M: A(x).

Example

∀x∈R:|x| ≥0

∃x∈Q:x+3≤12

∃!x∈R+ :x2=42

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IfA(x),x∈M andB(x),x∈Mare predicates, then

∀x∈M,B(x) :A(x) means ∀x∈M: (B(x)⇒A(x)),

∃x∈M,B(x) : A(x) means ∃x∈M: (A(x) & B(x)). Example

∀x∈R,x≥ −1:1+2x≤(1+x)2

∃x∈R,x≥0:x≥x2

Mathematics I - Introduction 17 / 48

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IfA(x),x∈M andB(x),x∈Mare predicates, then

∀x∈M,B(x) :A(x) means ∀x∈M: (B(x)⇒A(x)),

∃x∈M,B(x) : A(x) means ∃x∈M: (A(x) & B(x)).

Example

∀x∈R,x≥ −1:1+2x≤(1+x)2

∃x∈R,x≥0:x≥x2

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Negations of the statements with quantifiers:

¬(∀x∈M: A(x)) is the same as ∃x∈M:¬A(x),

¬(∃x∈M: A(x)) is the same as ∀x∈M:¬A(x). Example

Find negation

∀x∈R,x≥ −1:1+2x≤(1+x)2

∀x∈R,∀y∈R,x≥0,y≥0: x+y

2 ≥√

xy

∃x∈R,x≥0:x≥x2

Mathematics I - Introduction 18 / 48

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Negations of the statements with quantifiers:

¬(∀x∈M: A(x)) is the same as ∃x∈M:¬A(x),

¬(∃x∈M: A(x)) is the same as ∀x∈M:¬A(x).

Example Find negation

∀x∈R,x≥ −1:1+2x≤(1+x)2

∀x∈R,∀y∈R,x≥0,y≥0: x+y

2 ≥√

xy

∃x∈R,x≥0:x≥x2

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Methods of proofs

direct proof indirect proof

proof by contradiction mathematical induction

Mathematics I - Introduction 19 / 48

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Methods of proofs

direct proof indirect proof

proof by contradiction mathematical induction

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Induction

Exercise

n

X

i=1

(2i−1) =n2

Mathematics I - Introduction 20 / 48

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Rational numbers

The set of natural numbers

N={1,2,3,4, . . .}

The set of integers

Z=N∪ {0} ∪ {−n; n∈N}={. . . ,−2,−1,0,1,2, . . .}

The set of rational numbers Q=

p

q; p∈Z,q∈N

, where pq1

1 = pq2

2 if and only ifp1·q2 =p2·q1.

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Rational numbers

The set of natural numbers

N={1,2,3,4, . . .}

The set of integers

Z=N∪ {0} ∪ {−n; n∈N}={. . . ,−2,−1,0,1,2, . . .}

The set of rational numbers Q=

p

q; p∈Z,q∈N

, where pq1

1 = pq2

2 if and only ifp1·q2 =p2·q1.

Mathematics I - Introduction 21 / 48

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Rational numbers

The set of natural numbers

N={1,2,3,4, . . .}

The set of integers

Z=N∪ {0} ∪ {−n; n∈N}={. . . ,−2,−1,0,1,2, . . .}

The set of rational numbers Q=

p

q; p∈Z,q∈N

, where pq1

1 = pq2

2 if and only ifp1·q2 =p2·q1.

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Rational numbers

The set of natural numbers

N={1,2,3,4, . . .}

The set of integers

Z=N∪ {0} ∪ {−n; n∈N}={. . . ,−2,−1,0,1,2, . . .}

The set of rational numbers Q=

p

q; p∈Z,q∈N

, where pq1

1 = pq2

2 if and only ifp1·q2 =p2·q1.

Mathematics I - Introduction 21 / 48

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Rational numbers

The set of natural numbers

N={1,2,3,4, . . .}

The set of integers

Z=N∪ {0} ∪ {−n; n∈N}={. . . ,−2,−1,0,1,2, . . .}

The set of rational numbers Q=

p

q; p∈Z,q∈N

, where pq1

1 = pq2

2 if and only ifp1·q2 =p2·q1.

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Rational numbers

The set of natural numbers

N={1,2,3,4, . . .}

The set of integers

Z=N∪ {0} ∪ {−n; n∈N}={. . . ,−2,−1,0,1,2, . . .}

The set of rational numbers Q=

p

q; p∈Z,q∈N

, where pq1

1 = pq2

2 if and only ifp1·q2 =p2·q1.

Mathematics I - Introduction 21 / 48

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Rational numbers

The set of natural numbers

N={1,2,3,4, . . .}

The set of integers

Z=N∪ {0} ∪ {−n; n∈N}={. . . ,−2,−1,0,1,2, . . .}

The set of rational numbers

Q= p

q; p∈Z,q∈N

, where pq1

1 = pq2

2 if and only ifp1·q2 =p2·q1.

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Rational numbers

The set of natural numbers

N={1,2,3,4, . . .}

The set of integers

Z=N∪ {0} ∪ {−n; n∈N}={. . . ,−2,−1,0,1,2, . . .}

The set of rational numbers

Q= p

q; p∈Z,q∈N

, where pq1

1 = pq2

2 if and only ifp1·q2 =p2·q1.

Mathematics I - Introduction 21 / 48

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Rational numbers

The set of natural numbers

N={1,2,3,4, . . .}

The set of integers

Z=N∪ {0} ∪ {−n; n∈N}={. . . ,−2,−1,0,1,2, . . .}

The set of rational numbers Q=

p

q; p∈Z,q∈N

, where pq1

1 = pq2

2 if and only ifp1·q2 =p2·q1.

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Real numbers

By the set of real numbersRwe will understand a set on which there are operations ofadditionandmultiplication(denoted by +and·), and a relation ofordering(denoted by≤), such that it has the following three groups of properties.

I. The properties of addition and multiplication and their relationships.

II. The relationships of the ordering and the operations of addition and multiplication.

III. The infimum axiom.

Mathematics I - Introduction 22 / 48

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Real numbers

By the set of real numbersRwe will understand a set on which there are operations ofadditionandmultiplication(denoted by +and·), and a relation ofordering(denoted by≤), such that it has the following three groups of properties.

I. The properties of addition and multiplication and their relationships.

II. The relationships of the ordering and the operations of addition and multiplication.

III. The infimum axiom.

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The properties of addition and multiplication and their relationships:

∀x,y∈R: x+y=y+x(commutativity of addition),

∀x,y,z∈R: x+ (y+z) = (x+y) +z(associativity), There is an element inR(denoted by 0 and called azero element), such thatx+0=xfor everyx∈R,

∀x∈R∃y∈R: x+y=0 (yis called thenegativeofx, suchyis only one, denoted by−x),

∀x,y∈R: x·y=y·x(commutativity),

∀x,y,z∈R: x·(y·z) = (x·y)·z(associativity),

There is a non-zero element inR(calledidentity, denoted by 1), such that 1·x=xfor everyx∈R,

∀x∈R\ {0} ∃y∈R:x·y=1 (suchyis only one, denoted byx−1or 1x),

∀x,y,z∈R: (x+y)·z=x·z+y·z(distributivity).

Mathematics I - Introduction 23 / 48

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The properties of addition and multiplication and their relationships:

∀x,y∈R: x+y=y+x(commutativity of addition),

∀x,y,z∈R: x+ (y+z) = (x+y) +z(associativity), There is an element inR(denoted by 0 and called azero element), such thatx+0=xfor everyx∈R,

∀x∈R∃y∈R: x+y=0 (yis called thenegativeofx, suchyis only one, denoted by−x),

∀x,y∈R: x·y=y·x(commutativity),

∀x,y,z∈R: x·(y·z) = (x·y)·z(associativity),

There is a non-zero element inR(calledidentity, denoted by 1), such that 1·x=xfor everyx∈R,

∀x∈R\ {0} ∃y∈R:x·y=1 (suchyis only one, denoted byx−1or 1x),

∀x,y,z∈R: (x+y)·z=x·z+y·z(distributivity).

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The relationships of the ordering and the operations of addition and multiplication:

∀x,y,z∈R: (x≤y & y≤z)⇒x≤z(transitivity),

∀x,y∈R: (x≤y & y≤x)⇒x=y(weak antisymmetry),

∀x,y∈R: x≤y∨y≤x,

∀x,y,z∈R: x≤y⇒x+z≤y+z,

∀x,y∈R: (0≤x & 0≤y)⇒0≤x·y.

Mathematics I - Introduction 24 / 48

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The relationships of the ordering and the operations of addition and multiplication:

∀x,y,z∈R: (x≤y & y≤z)⇒x≤z(transitivity),

∀x,y∈R: (x≤y & y≤x)⇒x=y(weak antisymmetry),

∀x,y∈R: x≤y∨y≤x,

∀x,y,z∈R: x≤y⇒x+z≤y+z,

∀x,y∈R: (0≤x & 0≤y)⇒0≤x·y.

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Definition

We say that the setM ⊂Risbounded from belowif there exists a numbera∈Rsuch that for eachx∈Mwe havex≥a.

Such a numberais called alower boundof the setM.

Analogously we define the notions of aset bounded from above and anupper bound. We say that a setM ⊂Risboundedif it is bounded from above and below.

Exercise

Which sets are bounded from below? Bounded from above? Bounded?

A N

B {1,12,13,14,15, . . .} C R\Q∩(−3,2]

D {x∈R:x< π}

E (−∞,−1)∪ {0} ∪[1,∞)

Mathematics I - Introduction 25 / 48

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Definition

We say that the setM ⊂Risbounded from belowif there exists a numbera∈Rsuch that for eachx∈Mwe havex≥a.

Such a numberais called alower boundof the setM.

Analogously we define the notions of aset bounded from above and anupper bound. We say that a setM ⊂Risboundedif it is bounded from above and below.

Exercise

Which sets are bounded from below? Bounded from above? Bounded?

A N

B {1,12,13,14,15, . . .} C R\Q∩(−3,2]

D {x∈R:x< π}

E (−∞,−1)∪ {0} ∪[1,∞)

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Definition

We say that the setM ⊂Risbounded from belowif there exists a numbera∈Rsuch that for eachx∈Mwe havex≥a.

Such a numberais called alower boundof the setM.

Analogously we define the notions of aset bounded from above and anupper bound.

We say that a setM ⊂Risboundedif it is bounded from above and below.

Exercise

Which sets are bounded from below? Bounded from above? Bounded?

A N

B {1,12,13,14,15, . . .} C R\Q∩(−3,2]

D {x∈R:x< π}

E (−∞,−1)∪ {0} ∪[1,∞)

Mathematics I - Introduction 25 / 48

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Definition

We say that the setM ⊂Risbounded from belowif there exists a numbera∈Rsuch that for eachx∈Mwe havex≥a.

Such a numberais called alower boundof the setM.

Analogously we define the notions of aset bounded from above and anupper bound. We say that a setM ⊂Risboundedif it is bounded from above and below.

Exercise

Which sets are bounded from below? Bounded from above?

Bounded?

A N

B {1,12,13,14,15, . . .}

C R\Q∩(−3,2]

D {x∈R:x< π}

E (−∞,−1)∪ {0} ∪[1,∞)

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The infimum axiom:

LetMbe a non-empty set bounded from below. Then there exists a unique numberg∈Rsuch that

(i) ∀x∈M: x≥g,

(ii) ∀g ∈R,g >g∃x∈M: x<g.

The numbergis denoted byinfMand is called theinfimumof the setM.

Figure:

https://mathspandorabox.wordpress.com/2016/03/11/the-difference- between-supremum-and-infimum-equivalent-and-equal-set/

Mathematics I - Introduction 26 / 48

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The infimum axiom:

LetMbe a non-empty set bounded from below. Then there exists a unique numberg∈Rsuch that

(i) ∀x∈M: x≥g,

(ii) ∀g ∈R,g >g∃x∈M: x<g.

The numbergis denoted byinfMand is called theinfimumof the setM.

Figure:

https://mathspandorabox.wordpress.com/2016/03/11/the-difference- between-supremum-and-infimum-equivalent-and-equal-set/

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The infimum axiom:

LetMbe a non-empty set bounded from below. Then there exists a unique numberg∈Rsuch that

(i) ∀x∈M: x≥g,

(ii) ∀g ∈R,g >g∃x∈M: x<g.

The numbergis denoted byinfMand is called theinfimumof the setM.

Figure:

https://mathspandorabox.wordpress.com/2016/03/11/the-difference- between-supremum-and-infimum-equivalent-and-equal-set/

Mathematics I - Introduction 26 / 48

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Remark

The infimum axiom says that every non-empty set bounded from below has infimum.

The infimum of the setMis its greatest lower bound. The real numbers exist and are uniquely determined by the properties I–III.

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Remark

The infimum axiom says that every non-empty set bounded from below has infimum.

The infimum of the setMis its greatest lower bound.

The real numbers exist and are uniquely determined by the properties I–III.

Mathematics I - Introduction 27 / 48

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Remark

The infimum axiom says that every non-empty set bounded from below has infimum.

The infimum of the setMis its greatest lower bound.

The real numbers exist and are uniquely determined by the properties I–III.

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The following hold:

(i) ∀x∈R: x·0=0·x=0, (ii) ∀x∈R: −x= (−1)·x,

(iii) ∀x,y∈R: xy=0⇒(x=0∨y=0), (iv) ∀x∈R∀n∈N: x−n= (x−1)n,

(v) ∀x,y∈R: (x>0∧y>0)⇒xy>0,

(vi) ∀x∈R,x≥0∀y∈R,y≥0∀n∈N: x<y⇔xn <yn.

Mathematics I - Introduction 28 / 48

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Leta,b∈R,a≤b. We denote:

Anopen interval(a,b) ={x∈R; a<x<b}, Aclosed interval[a,b] ={x∈R; a≤x≤b}, Ahalf-open interval[a,b) ={x∈R; a≤x<b}, Ahalf-open interval(a,b] ={x∈R; a<x≤b}.

The pointais called theleft endpoint of the interval, The point bis called theright endpoint of the interval. A point in the interval which is not an endpoint is called aninner point of the interval.

Unbounded intervals:

(a,+∞) = {x∈R; a<x}, (−∞,a) ={x∈R; x<a}, analogically(−∞,a],[a,+∞)and(−∞,+∞).

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Leta,b∈R,a≤b. We denote:

Anopen interval(a,b) ={x∈R; a<x<b}, Aclosed interval[a,b] ={x∈R; a≤x≤b}, Ahalf-open interval[a,b) ={x∈R; a≤x<b}, Ahalf-open interval(a,b] ={x∈R; a<x≤b}.

The pointais called theleft endpoint of the interval, The point bis called theright endpoint of the interval. A point in the interval which is not an endpoint is called aninner point of the interval.

Unbounded intervals:

(a,+∞) = {x∈R; a<x}, (−∞,a) ={x∈R; x<a}, analogically(−∞,a],[a,+∞)and(−∞,+∞).

Mathematics I - Introduction 29 / 48

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Leta,b∈R,a≤b. We denote:

Anopen interval(a,b) ={x∈R; a<x<b}, Aclosed interval[a,b] ={x∈R; a≤x≤b}, Ahalf-open interval[a,b) ={x∈R; a≤x<b}, Ahalf-open interval(a,b] ={x∈R; a<x≤b}.

The pointais called theleft endpoint of the interval, The point bis called theright endpoint of the interval. A point in the interval which is not an endpoint is called aninner point of the interval.

Unbounded intervals:

(a,+∞) = {x∈R; a<x}, (−∞,a) ={x∈R; x<a}, analogically(−∞,a],[a,+∞)and(−∞,+∞).

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Label the Venn diagram withN,Q,Z,R,R\Q.

We haveN⊂Z⊂Q⊂R. If we transfer the addition and multiplication fromRto the above sets, we obtain the usual operations on these sets.

A real number that is not rational is calledirrational. The set R\Qis called theset of irrational numbers.

Mathematics I - Introduction 30 / 48

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Label the Venn diagram withN,Q,Z,R,R\Q.

We haveN⊂Z⊂Q⊂R. If we transfer the addition and multiplication fromRto the above sets, we obtain the usual operations on these sets.

A real number that is not rational is calledirrational. The set

\ is called theset of irrational numbers.

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Consequences of the infimum axiom

Definition

LetM ⊂R. A numberG∈Rsatisfying (i) ∀x∈M: x≤G,

(ii) ∀G ∈R,G <G∃x∈M: x>G, is called asupremumof the setM.

Theorem 1 (Supremum theorem)

Let M ⊂Rbe a non-empty set bounded from above. Then there exists a unique supremum of the set M.

The supremum of the setMis denoted bysupM. The following holds:supM =−inf(−M).

Mathematics I - Introduction 31 / 48

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Consequences of the infimum axiom

Definition

LetM ⊂R. A numberG∈Rsatisfying (i) ∀x∈M: x≤G,

(ii) ∀G ∈R,G <G∃x∈M: x>G, is called asupremumof the setM.

Theorem 1 (Supremum theorem)

Let M ⊂Rbe a non-empty set bounded from above. Then there exists a unique supremum of the set M.

The supremum of the setMis denoted bysupM. The following holds:supM =−inf(−M).

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Consequences of the infimum axiom

Definition

LetM ⊂R. A numberG∈Rsatisfying (i) ∀x∈M: x≤G,

(ii) ∀G ∈R,G <G∃x∈M: x>G, is called asupremumof the setM.

Theorem 1 (Supremum theorem)

Let M ⊂Rbe a non-empty set bounded from above. Then there exists a unique supremum of the set M.

The supremum of the setMis denoted bysupM.

The following holds:supM =−inf(−M).

Mathematics I - Introduction 31 / 48

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Consequences of the infimum axiom

Definition

LetM ⊂R. A numberG∈Rsatisfying (i) ∀x∈M: x≤G,

(ii) ∀G ∈R,G <G∃x∈M: x>G, is called asupremumof the setM.

Theorem 1 (Supremum theorem)

Let M ⊂Rbe a non-empty set bounded from above. Then there exists a unique supremum of the set M.

The supremum of the setMis denoted bysupM.

The following holds:supM =−inf(−M).

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Definition

LetM ⊂R. We say thatais amaximumof the setM(denoted bymaxM) ifais an upper bound ofManda∈M.

Analogously we define aminimumofM, denoted byminM.

Exercise

Find infimum, minimum, maximum and supremum:

1. {1,2,3,4}

2. [−2,3]

3. (−2,3) 4. (−2,3]

5. [−2,−1)∪(0,25]

6. (−7,−0)∪(1,2) 7. [0,∞)

8. {1,12,13,14, . . .}

9. N

Mathematics I - Introduction 32 / 48

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Theorem 2 (Archimedean property)

For every x∈Rthere exists n∈Nsatisfying n >x.

Theorem 3 (existence of an integer part)

For every r∈Rthere exists aninteger partof r, i.e. a number k∈Zsatisfying k ≤r<k+1. The integer part of r is

determined uniquely and it is denoted by[r].

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Theorem 2 (Archimedean property)

For every x∈Rthere exists n∈Nsatisfying n >x.

Theorem 3 (existence of an integer part)

For every r∈Rthere exists aninteger partof r, i.e. a number k∈Zsatisfying k ≤r<k+1. The integer part of r is

determined uniquely and it is denoted by[r].

Mathematics I - Introduction 33 / 48

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Theorem 4 (nth root)

For every x∈[0,+∞)and every n∈Nthere exists a unique y∈[0,+∞)satisfying yn =x.

Theorem 5 (density ofQandR\Q)

Let a,b∈R, a<b. Then there exist r∈Qsatisfying a<r<b and s∈R\Qsatisfying a<s<b.

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Theorem 4 (nth root)

For every x∈[0,+∞)and every n∈Nthere exists a unique y∈[0,+∞)satisfying yn =x.

Theorem 5 (density ofQandR\Q)

Let a,b∈R, a<b. Then there exist r∈Qsatisfying a<r<b and s∈R\Qsatisfying a<s<b.

Mathematics I - Introduction 34 / 48

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II. Limit of a sequence

Definition

Suppose that to each natural numbern∈Nwe assign a real numberan. Then we say that{an}n=1 is asequenceof real numbers. The numberanis called thenth memberof this sequence.

A sequence{an}n=1is equal to a sequence{bn}n=1ifan =bn holds for everyn∈N.

By theset of all members of the sequence{an}n=1 we understand the set

{x∈R; ∃n∈N: an =x}.

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II. Limit of a sequence

Definition

Suppose that to each natural numbern∈Nwe assign a real numberan. Then we say that{an}n=1 is asequenceof real numbers.

The numberanis called thenth memberof this sequence.

A sequence{an}n=1is equal to a sequence{bn}n=1ifan =bn holds for everyn∈N.

By theset of all members of the sequence{an}n=1 we understand the set

{x∈R; ∃n∈N: an =x}.

Mathematics I - Introduction 35 / 48

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II. Limit of a sequence

Definition

Suppose that to each natural numbern∈Nwe assign a real numberan. Then we say that{an}n=1 is asequenceof real numbers. The numberanis called thenth memberof this sequence.

A sequence{an}n=1is equal to a sequence{bn}n=1ifan =bn holds for everyn∈N.

By theset of all members of the sequence{an}n=1 we understand the set

{x∈R; ∃n∈N: an =x}.

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II. Limit of a sequence

Definition

Suppose that to each natural numbern∈Nwe assign a real numberan. Then we say that{an}n=1 is asequenceof real numbers. The numberanis called thenth memberof this sequence.

A sequence{an}n=1is equal to a sequence{bn}n=1ifan =bn holds for everyn∈N.

By theset of all members of the sequence{an}n=1 we understand the set

{x∈R; ∃n∈N: an =x}.

Mathematics I - Introduction 35 / 48

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II. Limit of a sequence

Definition

Suppose that to each natural numbern∈Nwe assign a real numberan. Then we say that{an}n=1 is asequenceof real numbers. The numberanis called thenth memberof this sequence.

A sequence{an}n=1is equal to a sequence{bn}n=1ifan =bn holds for everyn∈N.

By theset of all members of the sequence{an}n=1 we understand the set

{x∈R; ∃n∈N: an =x}.

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Posloupnost {1/n}

Mathematics I - Introduction 36 / 48

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Posloupnost {(–1)^n}

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Posloupnost {n}

Mathematics I - Introduction 36 / 48

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Posloupnost {P_n}

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Definition

We say that a sequence{an}is

bounded from aboveif the set of all members of this sequence is bounded from above,

bounded from belowif the set of all members of this sequence is bounded from below,

boundedif the set of all members of this sequence is bounded.

Mathematics I - Introduction 37 / 48

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Definition

We say that a sequence{an}is

bounded from aboveif the set of all members of this sequence is bounded from above,

bounded from belowif the set of all members of this sequence is bounded from below,

boundedif the set of all members of this sequence is bounded.

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Definition

We say that a sequence{an}is

bounded from aboveif the set of all members of this sequence is bounded from above,

bounded from belowif the set of all members of this sequence is bounded from below,

boundedif the set of all members of this sequence is bounded.

Mathematics I - Introduction 37 / 48

(111)

Definition

We say that a sequence{an}is

increasingifan <an+1 for everyn∈N,

decreasingifan >an+1 for everyn∈N, non-decreasingifan ≤an+1for everyn∈N, non-increasingifan ≥an+1for everyn∈N.

A sequence{an}ismonotoneif it satisfies one of the conditions above. A sequence{an}isstrictly monotoneif it is increasing or decreasing.

(112)

Definition

We say that a sequence{an}is

increasingifan <an+1 for everyn∈N, decreasingifan >an+1 for everyn∈N,

non-decreasingifan ≤an+1for everyn∈N, non-increasingifan ≥an+1for everyn∈N.

A sequence{an}ismonotoneif it satisfies one of the conditions above. A sequence{an}isstrictly monotoneif it is increasing or decreasing.

Mathematics I - Introduction 38 / 48

(113)

Definition

We say that a sequence{an}is

increasingifan <an+1 for everyn∈N, decreasingifan >an+1 for everyn∈N, non-decreasingifan ≤an+1for everyn∈N,

non-increasingifan ≥an+1for everyn∈N.

A sequence{an}ismonotoneif it satisfies one of the conditions above. A sequence{an}isstrictly monotoneif it is increasing or decreasing.

(114)

Definition

We say that a sequence{an}is

increasingifan <an+1 for everyn∈N, decreasingifan >an+1 for everyn∈N, non-decreasingifan ≤an+1for everyn∈N, non-increasingifan ≥an+1for everyn∈N.

A sequence{an}ismonotoneif it satisfies one of the conditions above. A sequence{an}isstrictly monotoneif it is increasing or decreasing.

Mathematics I - Introduction 38 / 48

(115)

Definition

We say that a sequence{an}is

increasingifan <an+1 for everyn∈N, decreasingifan >an+1 for everyn∈N, non-decreasingifan ≤an+1for everyn∈N, non-increasingifan ≥an+1for everyn∈N.

A sequence{an}ismonotoneif it satisfies one of the conditions above.

A sequence{an}isstrictly monotoneif it is increasing or decreasing.

(116)

Definition

We say that a sequence{an}is

increasingifan <an+1 for everyn∈N, decreasingifan >an+1 for everyn∈N, non-decreasingifan ≤an+1for everyn∈N, non-increasingifan ≥an+1for everyn∈N.

A sequence{an}ismonotoneif it satisfies one of the conditions above. A sequence{an}isstrictly monotoneif it is increasing or decreasing.

Mathematics I - Introduction 38 / 48

(117)

Definition

Let{an}and{bn}be sequences of real numbers.

By thesum of sequences{an}and{bn}we understand a sequence{an+bn}.

Analogously we define adifferenceand aproduct of sequences.

Suppose all the members of the sequence{bn}are

non-zero. Then by thequotient of sequences{an}and{bn} we understand a sequence{abn

n}.

Ifλ∈R, then by theλ-multiple of the sequence{an}we understand a sequence{λan}.

(118)

Definition

Let{an}and{bn}be sequences of real numbers.

By thesum of sequences{an}and{bn}we understand a sequence{an+bn}.

Analogously we define adifferenceand aproduct of sequences.

Suppose all the members of the sequence{bn}are

non-zero. Then by thequotient of sequences{an}and{bn} we understand a sequence{abn

n}.

Ifλ∈R, then by theλ-multiple of the sequence{an}we understand a sequence{λan}.

Mathematics I - Introduction 39 / 48

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