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On the first Zagreb index and multiplicative Zagreb coindices of graphs

Kinkar Ch. Das, Nihat Akgunes, Muge Togan, Aysun Yurttas, I. Naci Cangul, A. Sinan Cevik

Abstract

For a (molecular) graphGwith vertex setV(G) and edge setE(G), the first Zagreb index of G is defined as M1(G) = P

vi∈V(G)

dG(vi)2, wheredG(vi) is the degree of vertexviinG. Recently Xu et al. intro- duced two graphical invariantsY

1(G) = Y

vivj∈E(G)/

(dG(vi)+dG(vj)) and Y

2(G) = Y

vivj∈E(G)/

dG(vi)dG(vj) named as first multiplicative Zagreb coindex and second multiplicative Zagreb coindex, respectively. The Narumi-Katayama index of a graph G, denoted by N K(G), is equal to the product of the degrees of the vertices ofG, that is, N K(G) =

n

Y

i=1

dG(vi). The irregularity index t(G) of G is defined as the num- ber of distinct terms in the degree sequence of G. In this paper, we give some lower and upper bounds on the first Zagreb indexM1(G) of graphs and trees in terms of number of vertices, irregularity index, maxi- mum degree, and characterize the extremal graphs. Moreover, we obtain some lower and upper bounds on the (first and second) multiplicative Zagreb coindices of graphs and characterize the extremal graphs. Fi- nally, we present some relations between first Zagreb index and Narumi- Katayama index, and (first and second) multiplicative Zagreb index and coindices of graphs.

Key Words: First Zagreb index, First and Second multiplicative Zagreb coindex, Narumi-Katayama index.

2010 Mathematics Subject Classification: Primary 05C07; Secondary 05C12.

Received: 3.05.2014 Accepted: 2.10.2014.

153

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1 Introduction

We only consider finite, undirected and simple graphs throughout this paper.

Let G be a graph with vertex set V(G) (|V(G)| = n) and edge set E(G) (|E(G)|=m). For a graphG, we letdG(vi) be thedegree of a vertexviin G.

Themaximum vertex degree in G is denoted by ∆ and theminimum vertex degree by δ. For each vi ∈ V(G) , the set of neighbors of the vertex vi is denoted byNG(vi) . The irregularity indext(G) ofGis defined as the number of distinct terms in the degree sequence of G [1]. Denote byp, the number of pendent vertices inG. For terminology and notation not defined here, the reader is referred to Bondy and Murty [2].

Among the oldest and most studied topological indices, there are two clas- sical vertex-degree based topological indices–thefirst Zagreb index andsecond Zagreb index. These two indices first appeared in [14], and were elaborated in [15]. Later they were used in the structure-property model (see [20]). The first Zagreb indexM1(G) and the second Zagreb index M2(G) of a graphG are defined, respectively, as

M1(G) = X

vi∈V(G)

dG(vi)2, and

M2(G) = X

vivj∈E(G)

dG(vi)dG(vj).

During the past decades, numerous results concerning Zagreb indices have been put forward, see [3, 5, 7, 9, 13] and the references cited therein.

The Narumi-Katayama index of a graphG, denoted byN K(G), is equal to the product of the degrees of the vertices ofG, that is,

N K(G) =

n

Y

i=1

dG(vi).

Recently, the first and second multiplicative Zagreb indices [11, 18, 19] are defined as follows:

Y

1

(G) =

n

Y

i=1

dG(vi)2 and

Y

2

(G) = Y

vivj∈E(G)

dG(vi)dG(vj) =

n

Y

i=1

dG(vi)dG(vi).

The mathematical properties of the first and second multiplicative Zagreb indices have been given in [6, 11].

(3)

Xu et al. recently defined the multiplicative Zagreb coindices as follows [21]:

Y

1(G) = Y

vivj∈E(G)/

(dG(vi)+dG(vj)) and Y

2(G) = Y

vivj∈E(G)/

dG(vi)dG(vj).

In the same reference, it has been also given the mathematical properties of the first and second multiplicative Zagreb coindices.

The paper is organized as follows. In Section 2, we give some lower and upper bounds on the Zagreb indices of graphs and trees, and characterize the extremal graphs. In Section 3, we obtain some lower and upper bounds on multiplicative Zagreb coindices of graphs and characterize the extremal graphs. In Section 4, we present some relations between first Zagreb index and Narumi-Katayama index, and (first and second) multiplicative Zagreb index and coindices of graphs.

2 Bounds on the first Zagreb index of trees and graphs

In this section we give some lower and upper bounds on the first Zagreb index of trees and graphs in terms of n, t and ∆. For this we need the following result:

Lemma 1. Let T be a tree of order n with irregularity index t. Then the number of pendent vertices inT is

p≥

t−1

X

i=1

(dG(vi)−2) + 2 =

t−1

X

i=1

dG(vi)−2t+ 4, (1) where dG(v1) > dG(v2) > · · · > dG(vt−1) > dG(vt) = 1 and dG(vi) is the degree of the vertexvi in T. Moreover, the equality holds in (1)if and only if n=p+t−1.

Proof. For any graph G, it is well known that

n

X

i=1

dG(vi) = 2m, wherem is the number of edges inG.

Since T is a tree, we havem=n−1. Without loss of generality, we can assume thatdT(v1)≥dT(v2)≥ · · · ≥dT(vn) . Letpbe the number of pendent vertices inT. For i=n−p+ 1, n−p+ 2, . . . , n, we then havedT(vi) = 1.

(4)

Using these results, we get

n−p

X

i=1

dT(vi) +

n

X

i=n−p+1

dT(vi) = 2(n−1)⇐⇒2n−p−2 =

n−p

X

i=1

dT(vi)

⇐⇒ p=

n−p

X

i=1

(dT(vi)−2) + 2

⇐⇒ p≥

t−1

X

i=1

(dT(vi)−2) + 2 asn−p≥t−1 anddT(vi)≥2, (2) where i= 1,2, . . . , n−p. Moreover, the equality holds in (2) if and only if n=p+t−1. Hence the equality holds in (1) if and only if n=p+t−1.

Let Γ1 be the class of trees T = (V, E) such that T is a tree of ordern, irregularity indext, maximum degree ∆ and

∆ =t, dT(vi) = 1, i=t, t+ 1, . . . , n.

s s

s s

s s s

s

Figure 1:

Example 2. For a tree T1 as in Figure1, it is clear that n= 8,∆ =t= 4 and the number of pendent vertices are 5 (=n−t+ 1). Moreover, the degree sequence of treeT1 is(4,3, 2,1,1,1,1,1). HenceT1∈Γ.

Now we are ready to give an upper bound on the first Zagreb index of trees in terms ofn,tand ∆.

Theorem 3. LetT be a tree of ordernwith irregularity indextand maximum degree∆. Then

M1(T) ≤

n−3−t(t−3) 2

2−(t−1)(t−2)∆

+1

3(t3−3t2+ 2t+ 6) (3)

with equality if and only ifG∈Γ1.

(5)

Proof. Since the irregularity index of T is t, let us consider a set S(T) = {v1, v2, . . . , vt−1} such that ∆ = dG(v1) > dG(v2) > . . . > dG(vt−1) > 1, where dG(vi) is the degree of the vertex vi in T. Since dG(vi) ≤ ∆, for all vi∈V(T), we have

X

vi∈S(T)

dG(vi)2=

t−1

X

i=1

dG(vi)2

t−1

X

i=1

(∆−i+ 1)2

=

t−1

X

i=1

(∆ + 1)2+i2−2i(∆ + 1)

= (t−1)(∆ + 1)2+1

6(t−1)t(2t−1)

−(∆ + 1)t(t−1). (4) Moreover, we have

X

vi∈S(T)

dG(vi) =

t−1

X

i=1

dG(vi)≥2 + 3 +· · ·+t= t(t+ 1)

2 −1. (5)

Letpbe the number of pendent vertices in T. Now, M1(T) =

n

X

i=1

dG(vi)2

= X

vi∈V(T), dG(vi)=1

dG(vi)2+ X

vi∈S(T)

dG(vi)2

+ X

vi∈V(T)\S(T), dG(vi)>1

dG(vi)2

≤ p+

t−1

X

i=1

dG(vi)2+ (n−p−t+ 1)∆2 since dG(vi)≤∆

≤ (n−t+ 1)∆2−p(∆2−1) + (t−1)(∆ + 1)2 +1

6(t−1)t(2t−1)−(∆ + 1)t(t−1) by (4). (6)

(6)

By Lemma 1, the next step of last inequality is

≤ n∆2

t−1

X

i=1

dG(vi)−2t+ 4

!

(∆2−1)−(t2−3t+ 2)∆

+1 3t3−3

2t2+13

6 t−1 (7)

≤ n∆2

t(t−3)

2 + 3

(∆2−1)−(t2−3t+ 2)∆ + 1

3t3−3 2t2+13

6 t−1 by (5),

which gives the required result in (3). First part of the proof is completed.

Now suppose that the equality holds in (3). Then all the inequalities in the above must be equalities. From the equality in (7), we get

n=p+t−1 (by Lemma 1).

From the equality in (4), we get

dG(vi) = ∆−i+ 1, i= 1,2, . . . , t−1.

From the equality in (5), we get

dG(vi) =t−i+ 1, i= 1, 2, . . . , t−1

From the above results, we finally obtain ∆ =t and n=p+t−1. Thus we have

2n−4 =t(t−1), ∆ =t and dG(vi) = 1 for i=t, t+ 1, . . . , n.

HenceT ∈Γ1.

Conversely, let T ∈ Γ1. Then we have ∆ = t, p = n−t+ 1 and n =

1

2t(t−1) + 2. We have

M1(T) =t2+ (t−1)2+· · ·+ 22+ 12+ (n−t) = 1

3t3+t2−4 3t+ 2 and

(n−3)−t(t−3) 2

2 − (t−1)(t−2)∆ +1

3(t3−3t2+ 2t+ 6) = 1

3t3+t2−4 3t+ 2. This completes the theorem.

(7)

Let Γ2be the class of graphsH1= (V, E) such thatH1is a graph of order n, irregularity indext, maximum degree ∆ and

∆ =t, dG(vi) = 1, i=t+ 1, t+ 2, . . . , n.

Let Γ3be the class of graphsH2= (V, E) such thatH2is a graph of order n, irregularity indext, maximum degree ∆ and

dG(vi) =

∆−i+ 1 ; i= 1,2, . . . , t

∆ ; i=t+ 1, t+ 2, . . . , n .

G1 G2

r s r r

r r

r r

r r

r

Figure 2:

Example 4. Two graphsG1andG2 are depicted in Figure2. ForG1,n= 6,

∆ =t= 4and the number of pendent vertices are 3 (=n−t+ 1). Moreover, the degree sequence ofG1 is(4,3,2,1,1,1). HenceG1∈Γ2. ForG2,n= 5,

∆ =t = 3 and the number of maximum degree vertices are 3 (= n−t+ 1).

Moreover, the degree sequence ofG2 is(3,3,3,2, 1). HenceG2∈Γ3. Now we give some lower and upper bounds on the first Zagreb indexM1(G) of graphsGin terms ofn,tand ∆.

Theorem 5. Let Gbe a graph of order nwith irregularity indext and maxi- mum degree∆. Then

M1(G) ≥ 16t(t+ 1)(2t+ 1) +n−t and

M1(G) ≤ t(∆ + 1)2+16t(t+ 1)(2t+ 1)

−(∆ + 1)t(t+ 1) + (n−t)∆2





(8)

with the lower and upper bounds in(8) become equality if and only if G∈Γ2

andG∈Γ3, respectively.

Proof. Since the irregularity index of G is t, let us consider a set S(G) = {v1, v2, . . . , vt−1} such that ∆ = dG(v1) > dG(v2) > . . . > dG(vt−1) > 1,

(8)

wheredG(vi) is the degree of the vertexviinG. Sinceδ≤dG(vi)≤∆, for all vi∈V(G), we have

M1(G) =

n

X

i=1

dG(vi)2

= X

vi∈S(G)

dG(vi)2+ X

vi∈V(G)\S(G)

dG(vi)2

t

X

j=1

j2+ (n−t) 1 = 1

6t(t+ 1)(2t+ 1) +n−t and

M1(G) = X

vi∈S(G)

dG(vi)2+ X

vi∈V(G)\S(G)

dG(vi)2

t

X

j=1

(∆−j+ 1)2+ (n−t)∆2

= t(∆ + 1)2+1

6t(t+ 1)(2t+ 1)−(∆ + 1)t(t+ 1) + (n−t)∆2. First part of the proof is done.

Now suppose that there exits an equality for the lower bound in (8). Then we must have

∆ =t, dG(vi) =t−i+1, i= 1,2, . . . , t−1 anddG(vi) = 1, i=t, t+1, . . . , n.

HenceT ∈Γ2. On the other hand, if we suppose the existence of the equality for the upper bound in (8), then we must have

dG(vi) = ∆−i+ 1, i= 1,2, . . . , tanddG(vi) = ∆, i=t+ 1, t+ 2, . . . , n which impliesT ∈Γ3.

Conversely, by taking G∈Γ2 and G∈Γ3 respectively, one can easily see that the truthness of the both equalities in (8).

3 Bounds on the Multiplicative Zagreb coindices of graphs

Let Γ4be the class of graphs H4= (V, E) such thatH4 is a connected graph of maximum degree ∆, number of pendent verticesp(p >0) and

dH4(v1) =dH4(v2) =· · ·=dH4(vn−p) = ∆

(9)

and

dH4(vn−p+1) =dH4(vn−p+2) =· · ·=dH4(vn) = 1.

G3 G4

r s r s

r

r r s

s r r

s r r

Figure 3:

Example 6. LetG3andG4be the graphs depicted in Figure3. ForG3,n= 8,

∆ = 4, t = 2 and the number of pendent vertices are p= 4. Moreover, the degree sequence of graphG3is(4,4,4,4,1,1,1,1). HenceG3∈Γ4. ForG4, n= 6,∆ = 3, t= 2and the number of pendent vertices are p= 2. Moreover, the degree sequence ofG4 is(3, 3,3,3,1,1). HenceG4∈Γ4.

Now we give some lower and upper bounds on the first multiplicative Za- greb coindex in terms ofn,m,p, ∆ and non-pendent minimum degree δ.

Theorem 7. Let Gbe a connected graph of ordernwith medges, number of pendent vertices p, maximum degree ∆ and non-pendent minimum degree δ.

Also, for simplicity, let A denotes n(n−1)2 −m−p(p−1)2 −p(n−p−1). We then have

(i) Q

1(G)≥2

p(p−1)

2 (δ+ 1)p(n−p−1) (2δ)A, (9) (ii) Q

1(G)≤2

p(p−1)

2 (∆ + 1)p(n−p−1) (2∆)A. (10) The equality holds in both (9) and (10) if and only if G is isomorphic to a regular graph orG∈Γ4.

Proof. The number of vertex pairs (vi, vj) such that vivj ∈/ E(G) in G is n(n−1)

2 −m. SinceGis connected and the number of pendent vertices inG isp, then p(p−1)

2 is the number of vertex pairs (vi, vj) such thatvivj∈/E(G) withdG(vi) =dG(vj) = 1,p(n−p−1) is the number of vertex pairs (vi, vj) such that vivj ∈/ E(G) with dG(vi) = 1 or dG(vj) = 1, and n(n−1)

2 −

m− p(p−1)

2 −p(n−p−1) is the number of vertex pairs (vi, vj) such that

(10)

vivj ∈/ E(G) withdG(vi)>1 anddG(vj)>1. From the above, we get Y

1(G) = Y

vivj∈E(G)/

(dG(vi) +dG(vj)) which equals to

Y

vivj∈E(G)/ dG(vi)=1, dG(vj)=1

(dG(vi) +dG(vj)) Y

vivj∈E(G)/ dG(vi)>1, dG(vj)=1

(dG(vi) +dG(vj))

× Y

vivj∈E(G)/ dG(vi)>1, dG(vj)>1

(dG(vi) +dG(vj))

≥ 2

p(p−1)

2 (δ+ 1)p(n−p−1)(2δ)A,

whereAis defined as in the statement of the theorem. Moreover, the above equality holds if and only ifGis isomorphic to regular graph (p= 0) orG∈Γ4

(p >0).

Similarly, Q

1(G) equals to the Y

vivj∈E(G)/ dG(vi)=1, dG(vj)=1

(dG(vi) +dG(vj)) Y

vivj∈E(G)/ dG(vi)>1, dG(vj)=1

(dG(vi) +dG(vj))

× Y

vivj∈E(G)/ dG(vi)>1, dG(vj)>1

(dG(vi) +dG(vj))

≤ 2

p(p−1)

2 (∆ + 1)p(n−p−1) (2∆)A ,

whereAis defined as in the statement of the theorem. We note that the last inequality becomes equality if and only if G is isomorphic to regular graph (p= 0) orG∈Γ4 (p >0).

Hence the result.

The following inequality was obtained by Furuichi [12].

Lemma 8. [12] Fora1, a2, . . . , an≥0 andp1, p2, . . . , pn≥0satisfying

n

X

i=1

pi= 1,

(11)

there exists

n

X

i=1

piai

n

Y

i=1

apii≥nλ 1 n

n

X

i=1

ai

n

Y

i=1

a1/ni

!

, (11)

whereλ= min{p1, p2, . . . , pn}. Moreover, equality in (11)holds if and only if a1=a2=· · ·=an.

Now we obtain an upper bound onQ

2(G) of graphGin terms ofn,m,p, the first Zagreb indexM1(G) and the Narumi-Katayama indexN K(G) . Theorem 9. Let G be a connected graph of order n, m edges, p pendent vertices and maximum degree∆. Then

Y

2(G) ≤ (N K(G))p

"

(n−p−1)(2m−p) +p−M1(G) (n−p)(n−p−1)−2m+p

− (n−p)(n−∆−p−1) (n−p)(n−p−1)−2m+p

×

2m−p

n−p −(N K(G))1/(n−p)

#(n−p)(n−p−1)−2m+p

. (12) Additionally, the equality holds in(12)if and only ifG∈Γ4orGis isomorphic to a regular graph.

Proof. Sincepis the number of pendent vertices inG, we need to consider the proof in two cases as in the following.

Case(i) :The situation p >0:

We can assume that

dG(vn−p+1) =dG(vn−p+2) =· · ·=dG(vn) = 1. (13) Fori= 1,2, . . . , n−p, settingai=dG(vi) and

pi= n−dG(vi)−p−1 (n−p)(n−p−1)−2m+p

(12)

in (11), we get

n−p

X

i=1

dG(vi)(n−dG(vi)−p−1) (n−p)(n−p−1)−2m+p −

n−p

Y

i=1

dG(vi)n−dG(vi)−p−1

!

1

(n−p)(n−p−1)−2m+p

≥ (n−p)(n−∆−p−1) (n−p)(n−p−1)−2m+p

2m−p

n−p −n−pY

i=1

dG(vi)1/(n−p)!

(14) that is,

(n−p−1)(2m−p) +p−M1(G) (n−p)(n−p−1)−2m+p −

n−p

Q

i=1

dG(vi)n−dG(vi)−1

n−p

Q

i=1

dG(vi)p

1

(n−p)(n−p−1)−2m+p

≥ (n−p)(n−∆−p−1) (n−p)(n−p−1)−2m+p

2m−p

n−p −n−pY

i=1

dG(vi)1/(n−p)! .

After that, we actually have

n−p

Q

i=1

dG(vi)n−dG(vi)−1

n−p

Q

i=1

dG(vi)p

"

(n−p−1)(2m−p) +p−M1(G) (n−p)(n−p−1)−2m+p

− (n−p)(n−∆−p−1) (n−p)(n−p−1)−2m+p

× 2m−p

n−p −n−pY

i=1

dG(vi)1/(n−p)

!#(n−p)(n−p−1)−2m+p

.

Using the above result with (13) and the definition of Narumi-Katayama index, we get

Y

2(G) = Y

vivj∈E(G)/

dG(vi)dG(vj) =

n

Y

i=1

dG(vi)n−dG(vi)−1 (15)

(13)

≤ (N K(G))p

"

(n−p−1)(2m−p) +p−M1(G)

(n−p)(n−p−1)−2m+p − (n−p)(n−∆−p−1) (n−p)(n−p−1)−2m+p

×

2m−p

n−p −(N K(G))1/(n−p)

#(n−p)(n−p−1)−2m+p

.

Case(ii) :The situation p= 0:

Similarly as in Case (i), for i= 1,2, . . . , n, setting ai =dG(vi) and pi = n−dG(vi)−1

n(n−1)−2m in (11), we get Y

2(G) ≤

"

2m(n−1)−M1(G) n(n−1)−2m

− n(n−∆−1) n(n−1)−2m

2m

n −(N K(G))1/(n)

#n(n−1)−2m .

Therefore the first part of the proof is completed.

Now let us suppose that the equality holds in (12). Then all the inequalities in the above must be equalities. For Case (i), we havep > 0 and dG(v1) = dG(v2) = · · · = dG(vn−p) , by Lemma 8. HenceG ∈ Γ4. For Case (ii), we have p= 0 and dG(v1) =dG(v2) =· · · =dG(vn) , by Lemma 8. HenceG is isomorphic to a regular graph.

Conversely, letGbe isomorphic to ar-regular graph. Thenp= 0, 2m=nr, M1(G) =nr2 andN K(G) =rn. We have

Y

2(G) =rn(n−r−1)=

"

(n−1)2m−nr2

n(n−1)−2m − n(n−∆−1) n(n−1)−2m

2m n −r

#n(n−1)−2m

.

Let G ∈ Γ4. Then 2m = (n−p)∆ +p, M1(G) = (n−p)∆2+p and N K(G) = ∆n−p. Now we have

(N K(G))p

"

(n−p−1)(2m−p) +p−M1(G)

(n−p)(n−p−1)−2m+p − (n−p)(n−∆−p−1) (n−p)(n−p−1)−2m+p

×

2m−p

n−p −(N K(G))1/(n−p)

#(n−p)(n−p−1)−2m+p

= ∆p(n−p)(n−p)(n−p−∆−1)= ∆(n−p)(n−∆−1)=Y

2(G).

(14)

This completes the proof.

4 Some relations between first Zagreb index and Narumi- Katayama index, and multiplicative Zagreb index and coindices of graphs

One of the present authors compared between various topological indices in his previous research works [8, 10, 16]. In this section we obtain some relations among topological indices of graphs. The first example comes to our mind is for starK1, n−1(n≥3),

Y

2

(K1, n−1) = (n−1)n−1>1 =Y

2(K1, n−1), and the second example is for a cycleCn (n≥6),

Y

2

(Cn) = 22n<2n(n−3)=Y

2(Cn).

Now we can compare between the second multiplicative Zagreb index and the second multiplicative Zagreb coindex of graphsG.

Theorem 10. Let G be a graph without isolated vertices of order n with maximum degree∆ and minimum degree δ. If δ≥ n−12 (or ∆≤ n−12 ), then Y

2(G)≥ Y

2(G) orY

2(G)≤Y

2(G)

! . Proof. We clearly have

Y

2(G) = Y

vivj∈E(G)

dG(vi)dG(vj) =

n

Y

i=1

dG(vi)dG(vi) and

Y

2(G) = Y

vivj∈E(G)/

dG(vi)dG(vj) =

n

Y

i=1

dG(vi)n−dG(vi)−1. From the above, we get

Y

2(G) Y

2(G)

=

n

Y

i=1

dG(vi)2dG(vi)−(n−1)≥1 asdG(vi)≥δ≥n−1 2 . Similarly, one can easily prove thatY

2(G)≤Y

2(G) if ∆≤n−12 .

(15)

For the isomorphismG∼=K1, n−1(n≥8) , we have Y

2(G) +Y

2(G) = (n−1)n−1+ 1<(n−1)2+ 2(n−1)(n−2)/2

= Y

1(G) +Y

1(G).

However we can present the following result:

Theorem 11. Let Gbe a graph of order n. If dG(vi)≥2 for all vi∈V(G), then

Y

2(G) +Y

2(G)≥Y

1(G) +Y

1(G).

Proof. For each vivj ∈/ E(G), without loss of generality, we can assume that dG(vi)≥dG(vj). Thus we have

dG(vi)(dG(vj)−1)≥dG(vj) asdG(vk)≥2 for all vk∈V(G), that is,

dG(vi)dG(vj)≥dG(vi) +dG(vj) forvivj∈/E(G).

Using the above result, we get Y

2(G)−Y

1(G) = Y

vivj∈E(G)/

dG(vi)dG(vj)− Y

vivj∈E(G)/

(dG(vi) +dG(vi))

≥ 0 and

Y

2(G)−Y

1(G) = Y

vivj∈E(G)

dG(vi)dG(vj)−

n

Y

i=1

dG(vi)2

=

n

Y

i=1

dG(vi)dG(vi)

n

Y

i=1

dG(vi)2≥0 as dG(vi)≥2.

From the last two results, we get the required result.

Now we obtain the relation between the first multiplicative Zagreb coindex and the second multiplicative Zagreb coindex. Before, for simplicity, let us use the notationAfor

n(n−1)

2 −m−p(p−1)

2 −p(n−p−1) as in Theorem 7.

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Theorem 12. Let G be a connected graph of order n with m edges, number of pendent vertices p, maximum degree ∆ and non-pendent minimum degree δ. Then

(i) Y2

1(G)≥

δ+1 δ+ 2

p(n−p−1)

4A+p(p−1)2 Y

2(G) (16)

with equality if and only ifGis isomorphic to a regular graph orG∈Γ4, and

(ii) Y2

1(G) ≤ 4

p(p−1) 2

∆ δ + δ

∆+ 2 A

×

∆ + 1

∆+ 2

p(n−p−1)

Y

2(G) (17)

with equality if and only ifGis isomorphic to a regular graph orG∈Γ4. Proof. FordG(vi), dG(vj)>1, since ∆

δ ≥ dG(vi) dG(vj) ≥ δ

∆ , by [4], we have

4≤

sdG(vi) dG(vj)−

s dG(vj) dG(vi)

!2

+ 4 =

sdG(vi) dG(vj)+

s dG(vj) dG(vi)

!2

≤ r∆

δ + rδ

!2

(18) with equality holding if and only ifdG(vi) = ∆,dG(vj) =δfor anyvivj∈/E(G) anddG(vi)≥dG(vj).

In the proof of Theorem 7, we mentioned that p(p−1)

2 is the number of vertex pairs (vi, vj) such that vivj ∈/ E(G) with dG(vi) = dG(vj) = 1 , p(n−p−1) is the number of vertex pairs (vi, vj) such thatvivj∈/E(G) with dG(vi) = 1 ordG(vj) = 1, and n(n−1)

2 −m−p(p−1)

2 −p(n−p−1) is the number of vertex pairs (vi, vj) such that vivj ∈/ E(G) with dG(vi)> 1 and dG(vj)>1.

Using the above result with (18), we get Y

vivj∈E(G)/ dG(vi)>1, dG(vj)>1

dG(vi)

dG(vj)+dG(vj) dG(vi) + 2

≤ Y

vivj∈E(G)/

∆ δ + δ

∆ + 2

= ∆

δ + δ

∆+ 2 A

(17)

and

Y

vivj∈E(G)/ dG(vi)>1, dG(vj)>1

dG(vi)

dG(vj)+dG(vj) dG(vi) + 2

≥ 4A.

Moreover, the above two equalities hold if and only ifdG(vi) =dG(vj) for all vi andvj such that dG(vi)>1,dG(vj)>1.

Now we have

Y

vivj∈E(G)/ dG(vi)=1, dG(vj)=1

dG(vi)

dG(vj)+dG(vj) dG(vi) + 2

= 4

p(p−1) 2

and Y

vivj∈E(G)/ dG(vi)>1, dG(vj)=1

dG(vi)

dG(vj)+dG(vj) dG(vi) + 2

= Y

vivj∈E(G)/

dG(vi) + 1 dG(vi)+ 2

δ+1 δ+ 2

p(n−p−1)

with equality if and only ifdG(vi) =δ for allvi such that dG(vi)>1.

Also we have Y

vivj∈E(G)/ dG(vi)>1, dG(vj)=1

dG(vi)

dG(vj)+dG(vj) dG(vi) + 2

= Y

vivj∈E(G)/

dG(vi) + 1 dG(vi)+ 2

∆ + 1

∆ + 2

p(n−p−1)

with equality if and only ifdG(vi) = ∆ for allvi. By the definition, since we have

Y

1(G) = Y

vivj∈E(G)/

(dG(vi)+dG(vj)) and Y

2(G) = Y

vivj∈E(G)/

dG(vi)dG(vj),

(18)

we get Q2

1(G) Q

2(G) = Y

vivj∈E(G)/

(dG(vi) +dG(vj))2 dG(vi)dG(vj)

= Y

vivj∈E(G)/ dG(vi)=1, dG(vj)=1

dG(vi)

dG(vj)+dG(vj) dG(vi) + 2

Y

vivj∈E(G)/ dG(vi)>1, dG(vj)=1

dG(vi)

dG(vj)+dG(vj) dG(vi)+ 2

× Y

vivj∈E(G)/ dG(vi)>1, dG(vj)>1

dG(vi)

dG(vj)+dG(vj) dG(vi) + 2

δ+1 δ + 2

p(n−p−1) 4

n(n−1)

2 −m−p(n−p−1)

. Moreover, the above equality holds if and only ifG is isomorphic to regular graph (p= 0) orG∈Γ4 (p >0).

Similarly, Q2

1(G) Q

2(G) = Y

vivj∈E(G)/ dG(vi)=1, dG(vj)=1

dG(vi)

dG(vj)+dG(vj) dG(vi)+ 2

Y

vivj∈E(G)/ dG(vi)>1, dG(vj)=1

dG(vi)

dG(vj)+dG(vj) dG(vi)+ 2

× Y

vivj∈E(G)/ dG(vi)>1, dG(vj)>1

dG(vi)

dG(vj)+dG(vj) dG(vi)+ 2

≤ 4

p(p−1) 2

∆ + 1

∆ + 2

p(n−p−1) ∆ δ + δ

A

.

Moreover, the above equality holds if and only ifG is isomorphic to regular graph (p= 0) orG∈Γ4 (p >0). This completes the proof.

Similarly, we obtain another relation between the first multiplicative Za- greb coindex and second multiplicative Zagreb coindex. To do that, again let us use the notationAfor the algebraic statement n(n−1)2 −m−p(p−1)2 −p(n− p−1).

(19)

Theorem 13. Let G be a connected graph of order n with m edges, number of pendent vertices p, maximum degree ∆ and non-pendent minimum degree δ. Then

(i) Y

1(G)≥2

p(p−1) 2

2

A

× 1

∆ + 1

p(n−p−1) Y

2(G) (19)

with equality if and only ifGis isomorphic to a regular graph orG∈Γ4, and

(ii) Y

1(G)≤2

p(p−1) 2

2 δ

A

× 1

δ + 1

p(n−p−1)

Y

2(G) (20)

with equality if and only ifGis isomorphic to a regular graph orG∈Γ4. Proof. We have

Q

1(G) Q

2(G) = Y

vivj∈E(G)/

1

dG(vi)+ 1 dG(vj)

= Y

vivj∈E(G)/ dG(vi)=1, dG(vj)=1

1

dG(vi)+ 1 dG(vj)

Y

vivj∈E(G)/ dG(vi)>1, dG(vj)=1

1

dG(vi)+ 1 dG(vj)

× Y

vivj∈E(G)/ dG(vi)>1, dG(vj)>1

1

dG(vi)+ 1 dG(vj)

.

We haveδ≤dG(vi)≤∆ for non-pendent vertices. For vivj ∈/ E(G) with dG(vi)>1, dG(vj)>1 ,

2

∆ ≤ 1

dG(vi)+ 1 dG(vj) ≤2

δ and forvivj∈/ E(G) withdG(vi)>1, dG(vj) = 1 ,

1 + 1

∆ ≤ 1

dG(vi)+ 1

dG(vj)≤1 + 1 δ.

(20)

Using the same technique as in Theorem 12, we get the required result in (19) and (20). Moreover, the equality holds in (19) and (20) if and only ifG is isomorphic to regular graph (p= 0) or G∈Γ4 (p >0). This completes the proof.

Lemma 14. [17] Letx1, x2, . . . , xN be non negative numbers, and let α= 1

N

N

X

i=1

xi and γ=

N

Y

i=1

xi

!1/N

be their arithmetic and geometric means, respectively. Then 1

N(N−1) X

i<j

√ xi−√

xj2

≤α−γ≤ 1 N

X

i<j

√ xi−√

xj2 .

Moreover, equality holds if and only ifx1=x2=· · ·=xn.

Let Γ5be the class of graphsH5= (V, E) such thatH5is a graph of order nwith maximum degree ∆, minimum degreeδand

∆6=δ , dH5(v2) =dH5(v3) =· · ·=dH5(vn−1).

r

r r r

r

\

\\ r

r s r

s s

t

s

G5 G6

u u

t t

u t

u u

u s

u u

Figure 4:

Example 15. Let G5 and G6 be the graphs depicted in Figure 4. For G5, n= 9, ∆ = 7, δ = 1 and t = 3. Moreover, the degree sequence of graph G5 is (7,2,2,2,2,2,2,2, 1). Hence G5 ∈ Γ5. For G6, n = 6, ∆ = 3, δ = 1 and t = 2. Moreover, the degree sequence of G4 is (3, 3,3,3,3,1). Hence G6∈Γ5.

Now we obtain a relation between the first Zagreb index and Narumi- Katayama index of graphG.

(21)

Theorem 16. Let Gbe a graph of ordernwithm edges, maximum degree∆ and minimum degreeδ. Then

(n−2)(N K(G))2/(n−2) ≥ (∆δ)2/(n−2)

(n−3)(∆22) + (2m−∆−δ)2−(n−3)M1(G)

(21) and

(∆δ)2/(n−2)

(2m−∆−δ)2+ (∆22)−M1(G)

(n−2)(n−3)(N K(G))2/(n−2). (22) Moreover, both the above equalities hold if and only if G is isomorphic to a regular graph orG∈Γ5.

Proof. Setting in Lemma 14,N =n−2 andxi =dG(vi)2,i= 2,3, . . . , n−1, we get

α= 1 N

N

X

i=1

xi= 1 n−2

n−1

X

i=2

dG(vi)2= 1

n−2 M1(G)−∆2−δ2

γ=

N

Y

i=1

xi

!1/N

=

n−1

Y

i=2

dG(vi)2

!1/(n−2)

= Qn

i=1dG(vi)

∆δ

2/(n−2)

= (N K(G))2/(n−2) (∆δ)2/(n−2) and

X

2≤i<j≤n−1

√ xi−√

xj

2

= X

2≤i<j≤n−1

(dG(vi)−dG(vj))2

= (n−3)

n−1

X

i=2

dG(vi)2−2 X

2≤i<j≤n−1

dG(vi)dG(vj)

= (n−3)(M1(G)−∆2−δ2)−

n−1

X

i=2

dG(vi)(2m−dG(vi)−∆−δ)

= (n−2)M1(G)−(n−2)(∆22)−(2m−∆−δ)2.

(22)

Using the above results in Lemma 14, we get

(n−2)M1(G)−(n−2)(∆22)−(2m−∆−δ)2 (n−2)(n−3)

M1(G)−∆n−22−δ2(N K(G))(∆δ)2/(n−2)2/(n−2)

(n−2)M1(G)−(n−2)(∆22)−(2m−∆−δ)2

n−2 &, , (23)

that is,

(n−2)(N K(G))2/(n−2)

≥(∆δ)2/(n−2)

(n−3)(∆22) + (2m−∆−δ)2−(n−3)M1(G) and

(∆δ)2/(n−2)

(2m−∆−δ)2+ (∆22)−M1(G)

≥(n−2)(n−3)(N K(G))2/(n−2).

By Lemma 14, one can see easily that both the equality holds in (23) if and only ifdG(v2) =dG(v3) =· · ·=dG(vn−1) . First part of the proof is done.

First suppose that the equality holds in (21). Then dG(v2) =dG(v3) =

· · ·=dG(vn−1) . If ∆ =δ, thenGis isomorphic to a regular graph. Otherwise,

∆ 6= δ and hence G∈ Γ5. Conversely, one can see easily that the equality holds in (21) for regular graph.

Let G ∈ Γ5. Then we have ∆ 6= δ and dG(v2) = dG(v3) = · · · = dG(vn−1) =d, (say). Now,

(n−2)(N K(G))2/(n−2)= (n−2)d2(∆δ)2/(n−2),

(n−2)(n−3)(N K(G))2/(n−2)= (n−3)(n−2)d2(∆δ)2/(n−2), (∆δ)2/(n−2)

(2m−∆−δ)2+ (∆22)−M1(G)

= (n−3)(n−2)d2(∆δ)2/(n−2), and (∆δ)2/(n−2)

(n−3)(∆22) + (2m−∆−δ)2−(n−3)M1(G)

= (∆δ)2/(n−2)

(n−2)2d2−(n−3)(n−2)d2

= (n−2)d2(∆δ)2/(n−2). Hence the equality holds in (21).

Similarly, we can show that the equality holds in (22) if and only if G is isomorphic to a regular graph orG∈Γ5.

Acknowledgement. The first author is supported by the National Research Foundation funded by the Korean government with the grant no.

(23)

2013R1A1A2009341. The other authors are partially supported by Research Project Offices of N. Erbakan, Uludag and Selcuk Universities. This paper has been prepared during the Kinkar Ch. Das’s visit in Turkey that was par- tially funded by TUBITAK 2221-Programme. The fifth author is supported by Uludag University Research Fund, Project Nos: F-2015/23 and F-2015/17.

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Math. Comput. Chem. 63 (2) (2010) 433–440.

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Kinkar Ch. DAS,

Department of Mathematics, Sungkyunkwan University, Suwon 440-746, Republic of Korea.

Email: kinkardas2003@googlemail.com Nihat AKGUNES,

Department of Mathematics-Computer Sciences, Necmettin Erbakan University, Faculty of Science, Meram Yeniyol, 42100, Konya, Turkey.

Email: nakgunes@konya.edu.tr

Muge TOGAN, Aysun YURTTAS, Ismail Naci CANGUL Department of Mathematics,

Uludag University, Faculty of Science and Art, Gorukle Campus, 16059, Bursa, Turkey.

Emails: mugecapkin@yahoo.com.tr, aysunyurttas@gmail.com, cangul@uludag.edu.tr Ahmet Sinan CEVIK,

Department of Mathematics, Selcuk University, Faculty of Science, Campus, 42075, Konya, Turkey.

Email: sinan.cevik@selcuk.edu.tr

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